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 Regifting Robin

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pepperpot
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PostSubject: Regifting Robin   8/4/2009, 10:42

This is just too WEIRD!!

Let’s see if you can figure it out

To gifted friends. This is stumping. If you can figure out how she does it please let us know. Never even touched the cursor on my chosen number… Once, I did not even follow the directions, just looked at the number and she still got it! This will drive you crazy ~ You’ve got to try this!

http://www.regiftable.com/regiftingrobinpopup.html


A gift for you
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fay47
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PostSubject: Re: Regifting Robin   8/4/2009, 13:37

kind of spooky

Shocked

Fay
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wwe9112
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PostSubject: Re: Regifting Robin   8/4/2009, 15:34

lol thats weird...
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wwe9112
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PostSubject: Re: Regifting Robin   8/4/2009, 15:37

I found this explantion looking around the net:

It tells you to think of a two-digit number (e.g. 12). Then it tells you to subtract from that number each digit (e.g. 12-1-2=9). You will notice that no matter how many times you try it, you will always have a resulting number that is divisible by 9 (9,18,27,36,etc).

This is done because you are subtracting the number in the ones digit (2 in this case) which leaves you with a multiple of 10. Then you will subtract the number in the tens place which will result in a multiple of 9, because for every TEN you have, you subtract ONE...hence TEN minus ONE equals 9. (e.g. 20-2=18; 50-5=45)

So once you are assured of a multiple of 9, you will also note that each multiple of 9 has the same gift (or other answer) in the spot (e.g. 9=ball, 18=ball, 27=ball, etc.). The trick (with any trickery type of thing such as this) is to change the items listed each time. If you get a ball every time, you might be suspicious, but since the site automatically changes from a ball one time, then a scarf, then a phone, and so on, it seems as if they are actually reading your mind...

source: http://www.archerytalk.com/vb/showthread.php?t=836021
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fay47
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PostSubject: Re: Regifting Robin   8/4/2009, 17:11

I figured it had to be a math trick, but my poor old brain just too tired to try to figure it out lol!

thanks wee,

Fay
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Repa
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PostSubject: Re: Regifting Robin   8/4/2009, 18:47

That's it, wwe. Pretty clever!

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ruthsollid
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PostSubject: Re: Regifting Robin   8/4/2009, 19:28

Cool!!
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pepperpot
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PostSubject: Re: Regifting Robin   8/5/2009, 18:37

Well... no matter what I did... it never guess what was in number "1" for me.

But woohoo Wwe... now.... look whos the Geek!! LOL geek
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Rike
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PostSubject: Re: Regifting Robin   8/8/2009, 16:42

Very nice, wwe! You should major in Math!

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wwe9112
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PostSubject: Re: Regifting Robin   8/13/2009, 11:02

lol i said i got it from another site; i even posted the link... heaven above knows i wouldn't of gotten that... if i did figure anything out; it would of been, and was actually after the first couple of times of me doing it - that its always a multiple of 9... that explanation to me ws like chaneese with a dash of mexico and japan.
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fay47
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PostSubject: Re: Regifting Robin   8/13/2009, 11:34

wwe

I didn't figure it out either, but after you posted your explanation I went back and took a look using algebra (don't know if you have had algebra yet)

Any 2 digint number can be expressed as X* 10 + y
where x is the first digit and y is the 2nd digit
examples:
32: 3*10 + 2 = 30 + 2 = 32
45: 4*10 + 5 = 40 + 5 = 45

so :
if we start with:
x * 10 + y
first subtract the 2nd digit
( x * 10 + y) - y = x * 10 + y - y = x * 10
nuow subract the first ditit
(x * 10) - x = 10x - 1x = x(10-1) = x * 9
so it is always a mulitiple of 9

taking our 2 exmaples from above
32: 3*10 +2
subtract the 2nd digit
(3 * 10 + 2) - 2 = 3 * 10 + 2 - 2 = 3 * 10
subtract the 1st digit
(3 * 10) - 3 = 3 * (10-1) = 3*9
25: 2*10 +5
subtract the 2nd digit
(2 * 10 + 5) - 5 = 2 *10 + 5 - 5 = 2 * 10
subtract the 1st digit
(2 * 10) - 2 = 2 * (10-1) = 2*9

If you hanve not had algebra yet - the above might not make any sense.

Fay
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